FAD1014 L32 — Parametric Equations
Parametric equations express $x$ and $y$ coordinates as functions of a third independent variable (parameter $t$ or $\theta$). This lecture covers converting parametric equations to Cartesian form for conic sections.
Learning Outcomes
- Understand that $x$ and $y$ can be expressed as functions of a third independent variable
- Convert parametric equations to Cartesian equation
- Identify and describe the locus type with its details
- Sketch the locus obtained
Parametric Representation: Circle
Standard parametric equations: $$x = r \cos t \quad \text{and} \quad y = r \sin t$$
Cartesian form derivation: $$\cos t = \frac{x}{r}, \quad \sin t = \frac{y}{r}$$
Using $\cos^2 t + \sin^2 t = 1$: $$\frac{x^2}{r^2} + \frac{y^2}{r^2} = 1 \implies x^2 + y^2 = r^2$$
General form (center at $(h, k)$): $$x - h = r \cos t \quad \text{and} \quad y - k = r \sin t$$
Converts to: $$(x - h)^2 + (y - k)^2 = r^2$$
Parametric Representation: Parabola
Horizontal Parabola (opens right/left)
Parametric equations: $$x - h = at^2 \quad \text{and} \quad y - k = 2at$$
Cartesian form derivation: From $y - k = 2at \implies t = \frac{y - k}{2a}$
Substituting: $$x - h = a\left(\frac{y - k}{2a}\right)^2 = \frac{(y - k)^2}{4a}$$
$$(y - k)^2 = 4a(x - h)$$
Vertical Parabola (opens up/down)
Parametric equations: $$x - h = 2at \quad \text{and} \quad y - k = at^2$$
Cartesian form: $$(x - h)^2 = 4a(y - k)$$
Parametric Representation: Ellipse
Parametric equations: $$x - h = a \cos t \quad \text{and} \quad y - k = b \sin t$$
Cartesian form derivation: $$\cos t = \frac{x - h}{a}, \quad \sin t = \frac{y - k}{b}$$
Using $\cos^2 t + \sin^2 t = 1$: $$\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1$$
Parametric Representation: Hyperbola
Vertical Hyperbola (opens up/down)
Parametric equations: $$x - h = a \sec t \quad \text{and} \quad y - k = b \tan t$$
Cartesian form derivation: Using $1 + \tan^2 t = \sec^2 t$: $$\frac{(y - k)^2}{b^2} - \frac{(x - h)^2}{a^2} = 1$$
Horizontal Hyperbola (opens left/right)
Parametric equations: $$x - h = a \tan t \quad \text{and} \quad y - k = b \sec t$$
Cartesian form: $$\frac{(x - h)^2}{a^2} - \frac{(y - k)^2}{b^2} = 1$$
Practice Problems
Problem 1
A curve has parametric equations $x = \sin t - 2$ and $y = \cos t + 1$, where $t \in \mathbb{R}$.
Show that the Cartesian equation is a circle and sketch the graph.
Problem 2
A curve has parametric equations $x = \cot t + 1$ and $y = \csc^2 t - 4$, where $0 < t < \pi$.
Show that the Cartesian equation is a parabola, sketch the graph, and state the domain and range.
Problem 3
Find the standard form of the Cartesian equation:
(a) $x = 2t + 3$, $y = t^2$
(b) $x = 2\cos\theta$, $y = 3\sin\theta$
(c) $x = 5\sin\theta$, $y = 4\cos\theta$
(d) $x = \sec^2 t - 1$, $y = \tan t$
(e) $x = 2\sec t$, $y = \tan t - 8$
Key Identities Used
| Identity | Application |
|---|---|
| $\cos^2 t + \sin^2 t = 1$ | Circle, Ellipse |
| $1 + \tan^2 t = \sec^2 t$ | Hyperbola |
| $1 + \cot^2 t = \csc^2 t$ | Parabola |