FAD1022 L39-L42 — Atomic & Nuclear Physics — Formula Sheet

Comprehensive formula sheet for Atomic & Nuclear Physics (Lectures 39–42). Every equation from the lecture is included below, organized by topic.


1. Bohr's Model of the Hydrogen Atom

1.1 Angular Momentum Quantization

$$L = mvr = n\frac{h}{2\pi} = n\hbar$$

Variable Description Units
$L$ Angular momentum $\text{kg}\cdot\text{m}^2\cdot\text{s}^{-1}$
$m$ Mass of electron $9.1 \times 10^{-31}\ \text{kg}$
$v$ Orbital speed of electron $\text{m/s}$
$r$ Orbital radius $\text{m}$
$n$ Principal quantum number ($n = 1, 2, 3, \ldots$) dimensionless
$h$ Planck's constant $6.63 \times 10^{-34}\ \text{J}\cdot\text{s}$
$\hbar$ Reduced Planck constant $1.06 \times 10^{-34}\ \text{J}\cdot\text{s}$

1.2 Reduced Planck Constant

$$\hbar = \frac{h}{2\pi} \approx 1.06 \times 10^{-34}\ \text{J}\cdot\text{s}$$


1.3 Coulomb Force as Centripetal Force

From Newton's second law for circular motion, the electrostatic Coulomb force provides the centripetal acceleration:

$$\frac{e^2}{4\pi\varepsilon_0 r^2} = \frac{mv^2}{r}$$

Variable Description Units
$e$ Elementary charge $1.602 \times 10^{-19}\ \text{C}$
$\varepsilon_0$ Permittivity of free space $8.85 \times 10^{-12}\ \text{C}^2\cdot\text{N}^{-1}\cdot\text{m}^{-2}$
$r$ Orbital radius $\text{m}$
$m$ Electron mass $9.1 \times 10^{-31}\ \text{kg}$
$v$ Electron orbital speed $\text{m/s}$

1.4 Bohr Orbital Radius

$$r_n = \left(\frac{\varepsilon_0 h^2}{\pi m e^2}\right) n^2 \quad n = 1, 2, 3, \ldots$$

Practical form (Bohr radius):

$$\boxed{r_n = (5.29 \times 10^{-11}\ \text{m}), n^2 = a_0 n^2}$$

Variable Description Units
$r_n$ Radius of $n$-th orbit $\text{m}$
$a_0$ Bohr radius ($5.29 \times 10^{-11}\ \text{m}$) $\text{m}$
$n$ Principal quantum number dimensionless

1.5 Total Energy of the Hydrogen Atom

$$E = K + U = \frac{1}{2}mv^2 - \frac{ke^2}{r}$$

Using force balance ($K = \frac{ke^2}{2r}$), this simplifies to:

$$E = -\frac{ke^2}{2r}$$


1.6 Quantized Energy Levels

$$E_n = -\left(\frac{2\pi^2 m k^2 e^4}{h^2}\right)\frac{1}{n^2}$$

Practical form (hydrogen energy levels):

$$\boxed{E_n = -(13.6\ \text{eV})\frac{1}{n^2} \quad n = 1, 2, 3, \ldots}$$

Variable Description Units
$E_n$ Energy of $n$-th level $\text{eV}$ (or J)
$n$ Principal quantum number dimensionless

Key energy values:

$n$ State $E_n$
1 Ground state $-13.6\ \text{eV}$
2 1st excited state $-3.4\ \text{eV}$
3 2nd excited state $-1.51\ \text{eV}$
4 3rd excited state $-0.85\ \text{eV}$

1.7 Ionization Energy

Minimum energy to remove an electron from ground state to infinity ($n=1 \rightarrow n=\infty$):

$$\Delta E = E_\infty - E_1 = 0 - (-13.6\ \text{eV}) = 13.6\ \text{eV}$$


1.8 Atomic Transitions and Photon Energy

When an electron transitions between levels, the photon energy (emitted or absorbed) is:

$$\Delta E = hf = E_i - E_f$$

Expressed in terms of initial and final quantum numbers:

$$E_{\text{light}} = -13.6\left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right)\ \text{eV}$$

Variable Description Units
$\Delta E$ Energy difference / photon energy $\text{eV}$ or J
$h$ Planck's constant $6.63 \times 10^{-34}\ \text{J}\cdot\text{s}$
$f$ Photon frequency $\text{Hz}$
$E_i$ Initial energy level $\text{eV}$
$E_f$ Final energy level $\text{eV}$
$n_i$ Initial quantum number dimensionless
$n_f$ Final quantum number dimensionless

1.9 Spectral Series Summary

Series Transitions Region
Lyman $n \geq 2 \rightarrow n = 1$ Ultraviolet (UV)
Balmer $n \geq 3 \rightarrow n = 2$ Visible light
Paschen $n \geq 4 \rightarrow n = 3$ Infrared (IR)

2. Nuclear Structure

2.1 Nuclide Notation

$$^A_Z X \quad \text{where} \quad N = A - Z$$

Symbol Description
$A$ Mass number (protons + neutrons)
$Z$ Atomic number (protons)
$N$ Neutron number
$X$ Chemical symbol

2.2 Nuclear Radius

$$R = R_0 A^{1/3}$$

where $R_0 = 1.2 \times 10^{-15}\ \text{m} = 1.2\ \text{fm}$

Variable Description Units
$R$ Nuclear radius $\text{m}$ (or fm)
$R_0$ Empirical constant $1.2 \times 10^{-15}\ \text{m}$
$A$ Mass number dimensionless

2.3 Nuclear Volume

$$V = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi A R_0^3$$

Variable Description Units
$V$ Nuclear volume $\text{m}^3$
$R$ Nuclear radius $\text{m}$
$A$ Mass number dimensionless
$R_0$ Empirical constant $1.2 \times 10^{-15}\ \text{m}$

2.4 Nuclear Density

$$\rho \approx 2.3 \times 10^{17}\ \text{kg/m}^3$$

(Nuclear density is approximately constant for all nuclei.)


2.5 Subatomic Particle Masses

Particle Mass (kg) Charge (C) Atomic mass (u)
Proton ($m_p$) $1.67262 \times 10^{-27}$ $+e = +1.602 \times 10^{-19}$ $1.00728$
Neutron ($m_n$) $1.67492 \times 10^{-27}$ $0$ $1.00867$
Electron ($m_e$) $9.10938 \times 10^{-31}$ $-e = -1.602 \times 10^{-19}$ $0.000549$

3. Mass-Energy Equivalence & Atomic Mass Unit

3.1 Einstein's Mass-Energy Relation

$$E = mc^2$$

Variable Description Units
$E$ Energy J (or MeV)
$m$ Mass kg (or u)
$c$ Speed of light $3.00 \times 10^8\ \text{m/s}$

3.2 Atomic Mass Unit

$$1\ \text{u} = 1.6606 \times 10^{-27}\ \text{kg} \approx 1.66 \times 10^{-27}\ \text{kg}$$

(Defined as $\frac{1}{12}$ the mass of a neutral carbon-12 atom.)


3.3 Energy Equivalent of 1 u

In joules:

$$E = (1.66 \times 10^{-27})(3.00 \times 10^8)^2 = 1.49 \times 10^{-10}\ \text{J}$$

In mega-electronvolts:

$$E = \frac{1.49 \times 10^{-10}}{1.60 \times 10^{-19}} = 931.5\ \text{MeV}$$

Key conversion:

$$\boxed{1\ \text{u} = 931.5\ \text{MeV}/c^2}$$

or equivalently:

$$\boxed{c^2 = 931.5\ \text{MeV/u}}$$


3.4 Energy Unit Conversions

$$1\ \text{eV} = 1.602 \times 10^{-19}\ \text{J}$$

$$1\ \text{MeV} = 10^6\ \text{eV} = 1.602 \times 10^{-13}\ \text{J}$$


4. Mass Defect and Binding Energy

4.1 Mass Defect

The mass difference between constituent nucleons and the actual nucleus mass:

$$\boxed{\Delta m = Zm_p + Nm_n - m_N}$$

Variable Description Units
$\Delta m$ Mass defect kg (or u)
$Z$ Atomic number (protons) dimensionless
$m_p$ Proton mass kg (or u)
$N$ Neutron number dimensionless
$m_n$ Neutron mass kg (or u)
$m_N$ Actual mass of nucleus kg (or u)

4.2 Binding Energy

Energy required to break a nucleus into its constituent nucleons (or energy released when nucleons combine):

$$\boxed{E_B = (\Delta m)c^2 = [Zm_p + Nm_n - m_N]c^2}$$

In MeV (using $c^2 = 931.5\ \text{MeV/u}$):

$$\boxed{E_B = \Delta m \times 931.5\ \text{MeV/u}}$$

Variable Description Units
$E_B$ Binding energy J (or MeV)
$\Delta m$ Mass defect kg (or u)
$c$ Speed of light $3.00 \times 10^8\ \text{m/s}$

4.3 Binding Energy per Nucleon

$$\boxed{\frac{E_B}{A}}$$

  • Higher binding energy per nucleon $\rightarrow$ more stable nucleus.
  • Maximum stability at Fe-56: $E_B/A \approx 8.8\ \text{MeV/nucleon}$.
Variable Description Units
$E_B$ Total binding energy MeV
$A$ Mass number (total nucleons) dimensionless

5. Radioactive Decay

5.1 Types of Radioactive Decay

Decay Mode Emitted Particle Change in $Z$ Change in $A$ Condition
Alpha ($\alpha$) $^4_2\text{He}$ $-2$ $-4$ Nucleus too heavy
Beta minus ($\beta^-$) $^0_{-1}e$ $+1$ $0$ Too many neutrons
Positron ($\beta^+$) $^0_{+1}e$ $-1$ $0$ Too many protons
Gamma ($\gamma$) Photon $0$ $0$ Nucleus in excited state

5.2 Decay Law (Differential Form)

The rate of decay is proportional to the number of radioactive nuclei:

$$\boxed{\frac{dN}{dt} = -\lambda N}$$

Variable Description Units
$N$ Number of radioactive nuclei dimensionless
$t$ Time s (or any consistent unit)
$\lambda$ Decay constant $\text{s}^{-1}$ (or consistent inverse time)

5.3 Activity

The rate of decay (activity):

$$\boxed{A = \lambda N = -\frac{dN}{dt}}$$

Initial activity:

$$A_0 = \lambda N_0$$

Activity decay over time:

$$\boxed{A = A_0 e^{-\lambda t}}$$

Variable Description Units
$A$ Activity Bq (or Ci)
$\lambda$ Decay constant $\text{s}^{-1}$
$N$ Number of nuclei dimensionless
$t$ Time s
$A_0$ Initial activity Bq
$N_0$ Initial number of nuclei dimensionless

5.4 Activity Units

$$1\ \text{Bq} = 1\ \text{decay s}^{-1}$$

$$1\ \text{Ci} = 3.70 \times 10^{10}\ \text{Bq} = 3.70 \times 10^{10}\ \text{decays s}^{-1}$$


5.5 Exponential Decay Equation

Integrating the decay law:

$$\boxed{N(t) = N_0 e^{-\lambda t}}$$

Variable Description Units
$N(t)$ Number of nuclei at time $t$ dimensionless
$N_0$ Initial number of nuclei dimensionless
$\lambda$ Decay constant $\text{s}^{-1}$ (or consistent inverse time)
$t$ Time s (or consistent unit)

5.6 Half-Life

Time required for half the nuclei to decay:

$$\boxed{T_{1/2} = \frac{\ln 2}{\lambda} = \frac{0.693}{\lambda}}$$

Relationship to decay constant:

$$\lambda = \frac{0.693}{T_{1/2}}$$

Variable Description Units
$T_{1/2}$ Half-life s, yr, hr, etc.
$\lambda$ Decay constant $\text{s}^{-1}$, $\text{yr}^{-1}$, etc.

5.7 Fraction Remaining After Time $t$

From $N(t) = N_0 e^{-\lambda t}$ and $\lambda = \frac{\ln 2}{T_{1/2}}$:

$$\frac{N(t)}{N_0} = e^{-\lambda t} = \left(\frac{1}{2}\right)^{t/T_{1/2}}$$


6. Nuclear Reactions and Q-Value

6.1 Conservation Laws

In any nuclear reaction:

  1. Conservation of charge ($Z$): Total atomic number is conserved.
  2. Conservation of mass number ($A$): Total nucleon number is conserved.
  3. Conservation of energy: Total energy is conserved.

6.2 Q-Value (Reaction Energy)

Mass difference:

$$\boxed{\Delta m = \sum m_{\text{before}} - \sum m_{\text{after}}}$$

Reaction energy:

$$\boxed{Q = (\Delta m)c^2}$$

Condition Meaning
$\Delta m > 0$ or $Q > 0$ Exothermic (exoergic) — energy released as kinetic energy of products
$\Delta m < 0$ or $Q < 0$ Endothermic (endoergic) — energy must be absorbed for reaction to occur
Variable Description Units
$\Delta m$ Mass difference kg (or u)
$Q$ Reaction energy J (or MeV)
$c$ Speed of light $3.00 \times 10^8\ \text{m/s}$

Shortcut using atomic mass units:

$$Q = \Delta m \times 931.5\ \text{MeV/u}$$


6.3 Alpha Decay Example

$$^{226}{88}\text{Ra} \rightarrow ^{222}{86}\text{Rn} + ^{4}_{2}\text{He} + Q$$

$$\Delta m = m_{\text{Ra}} - (m_{\text{Rn}} + m_{\alpha})$$

$$Q = \Delta m \times 931.5\ \text{MeV}$$


6.4 Beta Decay Example

$$^{234}{90}\text{Th} \rightarrow ^{234}{91}\text{X} + ^{0}_{-1}e + Q$$

$$\Delta m = m_{\text{Th}} - (m_{\text{X}} + m_e)$$

$$Q = \Delta m \times 931.5\ \text{MeV}$$


7. Nuclear Fusion

7.1 Fusion Definition

Process where small nuclei combine to form larger nuclei, releasing energy.

Examples:

$$^{2}{1}\text{H} + {}^{2}{1}\text{H} \rightarrow {}^{3}{2}\text{He} + {}^{1}{0}\text{n} + \text{Energy}$$

$$^{2}{1}\text{H} + {}^{3}{1}\text{H} \rightarrow {}^{4}{2}\text{He} + {}^{1}{0}\text{n} + \text{Energy}$$

$$^{1}{1}\text{H} + {}^{2}{1}\text{H} \rightarrow {}^{3}_{2}\text{He} + \gamma$$


7.2 Fusion Energy Release

$$\text{Energy released} = (\text{Total } E_B \text{ of product}) - (\text{Total } E_B \text{ of reactants})$$

Or via mass defect:

$$\Delta m = (\text{total mass of reactants}) - (\text{total mass of products})$$

$$E = \Delta m , c^2 = \Delta m \times 931.5\ \text{MeV}$$

Worked example (two deuterons fusing):

$$^{2}{1}\text{H} + {}^{2}{1}\text{H} \rightarrow {}^{3}{1}\text{H} + {}^{1}{1}\text{H}$$

$$\Delta m = (2.0141 + 2.0141) - (3.0160 + 1.0078) = 0.0044\ \text{u}$$

$$E = 0.0044 \times 931.5 = 4.1\ \text{MeV}$$


8. Nuclear Fission

8.1 Fission Definition

A heavy nucleus splits into two lighter nuclei, releasing energy because fission products have greater average binding energy per nucleon than the parent.

Uranium-235 example:

$$^{1}{0}\text{n} + {}^{235}{92}\text{U} \rightarrow {}^{236}{92}\text{U}^* \rightarrow {}^{91}{36}\text{Kr} + {}^{142}{56}\text{Ba} + 3{}^{1}{0}\text{n} + Q$$


8.2 Fission Energy Calculation

$$\Delta m = (m_{\text{U}} + m_n) - (m_{\text{product 1}} + m_{\text{product 2}} + 3m_n)$$

$$Q = \Delta m , c^2 = \Delta m \times 931.5\ \text{MeV}$$

Worked example:

$$^{235}{92}\text{U} + {}^{1}{0}\text{n} \rightarrow {}^{85}{35}\text{Br} + {}^{148}{57}\text{La} + 3{}^{1}_{0}\text{n} + Q$$

Given masses:

  • $m_n = 1.00867\ \text{u}$
  • $m_{^{85}\text{Br}} = 84.91179\ \text{u}$
  • $m_{^{148}\text{La}} = 147.91718\ \text{u}$
  • $m_{^{235}\text{U}} = 235.04392\ \text{u}$

$$\Delta m = (235.04392 + 1.00867) - (84.91179 + 147.91718 + 3 \times 1.00867)$$

$$\Delta m = 236.05259 - 235.85498 = 0.19761\ \text{u}$$

$$Q = 0.19761 \times 931.5 = 184.074\ \text{MeV}$$


9. Carbon Dating

9.1 Carbon-14 Decay Constant

$$\lambda = \frac{\ln 2}{t_{1/2}} = \frac{0.693}{5730\ \text{yr}} = 1.21 \times 10^{-4}\ \text{yr}^{-1}$$


9.2 Age from Remaining Activity

Using $N(t) = N_0 e^{-\lambda t}$, solving for $t$:

$$\frac{N(t)}{N_0} = e^{-\lambda t}$$

$$\ln\left(\frac{N(t)}{N_0}\right) = -\lambda t$$

$$\boxed{t = -\frac{1}{\lambda}\ln\left(\frac{N(t)}{N_0}\right) = \frac{1}{\lambda}\ln\left(\frac{N_0}{N(t)}\right)}$$

Alternatively, using half-life:

$$\boxed{t = \frac{T_{1/2} \cdot \ln(N_0/N)}{\ln 2}}$$

Variable Description Units
$t$ Age of sample yr
$\lambda$ Decay constant $\text{yr}^{-1}$
$T_{1/2}$ Half-life ($5730$ yr for C-14) yr
$N_0$ Initial number of nuclei / initial activity
$N(t)$ Remaining number / remaining activity

9.3 Number of Nuclei in a Sample

$$N_0 = \frac{N_A}{M} \times m_{\text{sample}}$$

For carbon in 1.0 kg:

$$N_0 = \frac{6.022 \times 10^{23}}{14} \times 1000 = 4.30 \times 10^{25}\ \text{atoms}$$

Variable Description Units
$N_A$ Avogadro's number $6.022 \times 10^{23}\ \text{mol}^{-1}$
$M$ Molar mass g/mol
$m_{\text{sample}}$ Mass of sample g

10. Key Constants Summary

Constant Symbol Value
Speed of light $c$ $3.00 \times 10^8\ \text{m/s}$
Planck's constant $h$ $6.63 \times 10^{-34}\ \text{J}\cdot\text{s}$
Reduced Planck constant $\hbar$ $1.06 \times 10^{-34}\ \text{J}\cdot\text{s}$
Elementary charge $e$ $1.602 \times 10^{-19}\ \text{C}$
Electron mass $m_e$ $9.11 \times 10^{-31}\ \text{kg}$
Proton mass $m_p$ $1.673 \times 10^{-27}\ \text{kg}$
Neutron mass $m_n$ $1.675 \times 10^{-27}\ \text{kg}$
Permittivity of free space $\varepsilon_0$ $8.85 \times 10^{-12}\ \text{C}^2\cdot\text{N}^{-1}\cdot\text{m}^{-2}$
Coulomb constant $k = \frac{1}{4\pi\varepsilon_0}$ $8.99 \times 10^9\ \text{N}\cdot\text{m}^2\cdot\text{C}^{-2}$
Atomic mass unit $1\ \text{u}$ $1.661 \times 10^{-27}\ \text{kg}$
Energy equivalent of 1 u $c^2$ $931.5\ \text{MeV/u}$
1 eV in joules $1.602 \times 10^{-19}\ \text{J}$
Bohr radius $a_0$ $5.29 \times 10^{-11}\ \text{m}$
Ionization energy of H $E_\infty - E_1$ $13.6\ \text{eV}$
Avogadro's number $N_A$ $6.022 \times 10^{23}\ \text{mol}^{-1}$
Nuclear radius constant $R_0$ $1.2 \times 10^{-15}\ \text{m} = 1.2\ \text{fm}$

Formula sheet extracted from FAD1022 L39-L42 — Atomic & Nuclear Physics — comprehensive coverage of all equations for finals revision.