FAD1022 L44 — Photons and Photoelectric Effect — Formula Sheet

A complete reference of all formulas, equations, and key relationships from Lecture 44 on Photons and the Photoelectric Effect.


1. Fundamental Constants

Symbol Value Description
$c$ $3.00 \times 10^8 \text{ m/s}$ Speed of light in vacuum
$h$ $6.63 \times 10^{-34} \text{ J}\cdot\text{s}$ Planck's constant
$e$ $1.60 \times 10^{-19} \text{ C}$ Elementary charge (magnitude of electron charge)
$m_e$ $9.11 \times 10^{-31} \text{ kg}$ Mass of electron

Conversion Factor: $$1 \text{ eV} = 1.60 \times 10^{-19} \text{ J}$$


2. Photon Energy & Properties

Core Photon Energy Equations

The energy of a single photon is determined by its frequency or wavelength:

$$E = hf = \frac{hc}{\lambda}$$

Where:

  • $E$ = energy of the photon ($\text{J}$ or $\text{eV}$)
  • $h$ = Planck's constant ($6.63 \times 10^{-34} \text{ J}\cdot\text{s}$)
  • $f$ = frequency of light ($\text{Hz}$)
  • $c$ = speed of light ($3.00 \times 10^8 \text{ m/s}$)
  • $\lambda$ = wavelength ($\text{m}$)

Frequency-Wavelength Relationship

For any electromagnetic wave (including photons):

$$c = f\lambda \quad \Longrightarrow \quad f = \frac{c}{\lambda} \quad \text{or} \quad \lambda = \frac{c}{f}$$

Derived Photon Energy Forms

Rearranging the core equation for specific variables:

$$f = \frac{E}{h} \qquad \lambda = \frac{hc}{E} \qquad h = \frac{E}{f}$$

Key Relationships

  • Higher frequency $\rightarrow$ Higher photon energy
  • Shorter wavelength $\rightarrow$ Higher photon energy

3. Work Function & Threshold Frequency

Work Function ($\phi$)

The minimum energy required to remove an electron from a metal surface.

$$\phi = hf_0$$

Where:

  • $\phi$ = work function ($\text{J}$ or $\text{eV}$)
  • $f_0$ = threshold (cutoff) frequency ($\text{Hz}$)

Threshold (Cutoff) Frequency

The minimum frequency of incident light required to eject electrons from a specific metal:

$$f_0 = \frac{\phi}{h}$$

Cutoff (Threshold) Wavelength

The maximum wavelength of incident light that can still eject electrons:

$$\lambda_c = \frac{hc}{\phi}$$

Where:

  • $\lambda_c$ = cutoff wavelength ($\text{m}$ or $\text{nm}$)

Cutoff Frequency from Cutoff Wavelength

$$f_c = \frac{c}{\lambda_c}$$


4. The Photoelectric Effect — Core Equations

Einstein's Photoelectric Equation

The maximum kinetic energy of an ejected photoelectron equals the photon energy minus the work function:

$$KE_{max} = hf - \phi$$

Alternative forms using wavelength:

$$KE_{max} = \frac{hc}{\lambda} - \phi$$

Where:

  • $KE_{max}$ = maximum kinetic energy of ejected electron ($\text{J}$ or $\text{eV}$)
  • $hf$ = incident photon energy ($\text{J}$ or $\text{eV}$)
  • $\phi$ = work function of the metal ($\text{J}$ or $\text{eV}$)

Maximum Kinetic Energy from Velocity

If the maximum speed of ejected electrons is known:

$$KE_{max} = \frac{1}{2} m_e v_{max}^2$$

Where:

  • $m_e$ = mass of electron ($9.11 \times 10^{-31} \text{ kg}$)
  • $v_{max}$ = maximum speed of ejected electrons ($\text{m/s}$)

Solving for Work Function

When photon energy and maximum kinetic energy are known:

$$\phi = hf - KE_{max} = \frac{hc}{\lambda} - KE_{max}$$


5. Stopping Potential

Definition

The minimum voltage required to stop the most energetic photoelectrons.

$$KE_{max} = eV_s$$

Where:

  • $e$ = elementary charge ($1.60 \times 10^{-19} \text{ C}$)
  • $V_s$ = stopping potential ($\text{V}$)

Combined with Photoelectric Equation

$$eV_s = hf - \phi$$

Or solving for stopping potential:

$$V_s = \frac{hf - \phi}{e} = \frac{KE_{max}}{e}$$


6. Emission Conditions (Decision Rules)

The outcome depends on comparing photon energy to the work function:

Condition Physical Result
$hf < \phi$ No electrons emitted — photon energy insufficient
$hf = \phi$ Electrons escape with zero kinetic energy ($KE_{max} = 0$)
$hf > \phi$ Electrons emitted with $KE_{max} = hf - \phi$

In terms of frequency vs. threshold frequency:

Condition Physical Result
$f < f_0$ No photoelectric effect
$f = f_0$ Emission at threshold; $KE_{max} = 0$
$f > f_0$ Photoelectric effect occurs

In terms of wavelength vs. cutoff wavelength:

Condition Physical Result
$\lambda > \lambda_c$ No photoelectric effect (frequency too low)
$\lambda = \lambda_c$ Emission at threshold; $KE_{max} = 0$
$\lambda < \lambda_c$ Photoelectric effect occurs

7. Role of Intensity vs. Frequency

Property Controls Formula Link
Frequency ($f$) Whether electrons are emitted Energy per photon: $E = hf$
Intensity ($I$) How many electrons are emitted Number of photons per unit area/time

Important: Intensity does not affect the kinetic energy of individual electrons — only the number of photons (and thus the number of ejected electrons).


8. Unit Conversion Equations

Joules to Electronvolts

$$E , (\text{eV}) = \frac{E , (\text{J})}{1.60 \times 10^{-19} \text{ J/eV}}$$

Electronvolts to Joules

$$E , (\text{J}) = E , (\text{eV}) \times 1.60 \times 10^{-19} \text{ J/eV}$$

Wavelength Conversions

$$1 \text{ nm} = 10^{-9} \text{ m} \qquad 1 \text{ Å} = 10^{-10} \text{ m}$$


9. Quick Reference — All Equations at a Glance

Photon Energy

$$E = hf = \frac{hc}{\lambda}$$

Wave Relations

$$c = f\lambda$$

Work Function

$$\phi = hf_0 = \frac{hc}{\lambda_c}$$

Threshold / Cutoff Frequency

$$f_0 = \frac{\phi}{h}$$

Cutoff Wavelength

$$\lambda_c = \frac{hc}{\phi}$$

Photoelectric Effect (Einstein)

$$KE_{max} = hf - \phi = \frac{hc}{\lambda} - \phi$$

Kinetic Energy from Speed

$$KE_{max} = \frac{1}{2}m_e v_{max}^2$$

Stopping Potential

$$KE_{max} = eV_s$$

Solving for Work Function

$$\phi = \frac{hc}{\lambda} - KE_{max}$$

Stopping Potential from Photoelectric Equation

$$V_s = \frac{hf - \phi}{e}$$


10. Key Variables Summary

Variable Meaning Common Units
$E$ Photon energy J, eV
$h$ Planck's constant $6.63 \times 10^{-34} \text{ J}\cdot\text{s}$
$f$ Frequency Hz ($\text{s}^{-1}$)
$f_0$, $f_c$ Threshold / cutoff frequency Hz
$\lambda$ Wavelength m, nm
$\lambda_c$ Cutoff wavelength m, nm
$c$ Speed of light $3.00 \times 10^8 \text{ m/s}$
$\phi$ Work function J, eV
$KE_{max}$ Maximum kinetic energy of electron J, eV
$v_{max}$ Maximum electron speed m/s
$m_e$ Electron mass $9.11 \times 10^{-31} \text{ kg}$
$e$ Elementary charge $1.60 \times 10^{-19} \text{ C}$
$V_s$ Stopping potential V
$I$ Intensity $\text{W/m}^2$

Extracted from: FAD1022 L44 — Photons and Photoelectric Effect Course: FAD1022 - Basic Physics II