Terminal Voltage

Terminal Voltage ($V$) is the operating potential difference measured across the terminals of a source (battery, generator, etc.) when connected to a circuit. It represents the actual voltage available to drive current through the external circuit.

Definition

Terminal voltage is the potential difference between the positive and negative terminals of a source under operating conditions:

$$V = V_{+} - V_{-}$$

Relationship to EMF and Internal Resistance

Terminal voltage depends on:

  1. The EMF of the source ($\varepsilon$)
  2. The current flowing ($I$)
  3. The internal resistance of the source ($r$)

Fundamental Equation

$$V = \varepsilon - Ir$$

This is the most common form, applicable when the source is delivering current (discharging).

Three Operating Conditions

1. Discharging (Delivering Current)

When the source supplies current to an external load:

$$V = \varepsilon - Ir$$

  • Terminal voltage is less than EMF
  • The $Ir$ term represents the voltage drop across internal resistance
  • As current increases, terminal voltage decreases
  • This is the normal operating mode for batteries powering devices

Physical interpretation: Some energy is lost overcoming the internal resistance, leaving less voltage for the external circuit.

2. Charging (Receiving Current)

When an external source forces current into the battery:

$$V = \varepsilon + Ir$$

  • Terminal voltage is greater than EMF
  • Higher voltage is needed to overcome both the chemical EMF and internal resistance
  • Used when charging rechargeable batteries

Example: A 12 V car battery being charged at high current might have a terminal voltage of 14-15 V.

3. Open Circuit (No Current)

When no current flows ($I = 0$):

$$V = \varepsilon$$

  • Terminal voltage equals EMF
  • No voltage drop across internal resistance
  • Used to measure the true EMF of a source with a high-resistance voltmeter

Visual Representation

flowchart LR
    subgraph Source["EMF Source with Internal Resistance"]
        direction TB
        E["EMF ε<br/>↑<br/>Ideal Source"] --- Rint["Internal<br/>Resistance r"]
    end
    
    A["Terminal +<br/>V = ?"] --- Load["External<br/>Load R"]
    Load --- B["Terminal -"]
    
    Rint --- A
    E --- B
    
    style E fill:#90EE90
    style Rint fill:#FFB6C1
    style Load fill:#87CEEB

Complete Circuit Analysis

Voltage Drops in Series

$$\varepsilon = V_{\text{external}} + V_{\text{internal}}$$

where:

  • $V_{\text{external}} = IR$ (voltage across external load)
  • $V_{\text{internal}} = Ir$ (voltage drop across internal resistance)

Therefore: $$\varepsilon = IR + Ir = I(R + r)$$

Current in the Circuit

$$I = \frac{\varepsilon}{R + r}$$

Substituting back to find terminal voltage:

$$V = IR = \varepsilon \cdot \frac{R}{R + r}$$

This shows terminal voltage is a fraction of EMF determined by the ratio of external to total resistance.

Factors Affecting Terminal Voltage

1. Load Resistance

As load resistance $R$ decreases:

  • Current $I$ increases
  • Terminal voltage $V$ decreases
  • When $R \to 0$ (short circuit): $V \to 0$ and $I \to \varepsilon/r$ (maximum current)

2. Internal Resistance

Higher internal resistance causes:

  • Greater voltage drop for the same current
  • Lower terminal voltage under load
  • More power dissipated as heat within the source

3. Current Drawn

The relationship between terminal voltage and current is linear:

$$V = \varepsilon - Ir$$

Plotting $V$ vs $I$ gives a straight line with:

  • Intercept = EMF (at $I = 0$)
  • Slope = $-r$ (negative internal resistance)

Terminal Voltage vs Current Graph

Terminal
Voltage V
    ↑
    │
 ε ─┼────────────●─────
    │           /│
    │          / │
    │         /  │
    │        /   │
    │       /    │
    │      /     │
    │     /      │
    │    /       │
    │   /        │
    │  /         │
    │ /          │
    │/           │
  0 ┼────────────┼────→ Current I
    │            │
    └────────────┘
         I_max = ε/r
  • At $I = 0$: $V = \varepsilon$ (open circuit)
  • At $I = I_{\text{max}} = \varepsilon/r$: $V = 0$ (short circuit)

Practical Implications

Battery Behavior

  • Fresh battery: Low internal resistance → terminal voltage stays close to EMF even under load
  • Used battery: High internal resistance → terminal voltage drops significantly under load
  • Old batteries: May show near-normal open-circuit voltage but fail under load due to high internal resistance

Measuring Battery Health

Measuring terminal voltage under load is a better indicator of battery condition than open-circuit voltage because it reveals the internal resistance.

Circuit Design

  • For maximum voltage delivery: Use source with low internal resistance
  • For maximum power transfer: Match load resistance to internal resistance ($R = r$)
  • For stable voltage: Use source with $r \ll R$ (internal resistance much smaller than load)

Worked Examples

Example 1: Basic Terminal Voltage

Problem: A 12 V battery has internal resistance 0.1 Ω. What is its terminal voltage when supplying 5 A?

Solution:

$$V = \varepsilon - Ir = 12 - (5)(0.1) = 12 - 0.5 = 11.5 \text{ V}$$

Example 2: Finding EMF from Terminal Voltage

Problem: A battery has terminal voltage 8.5 V when delivering 3 A. Its internal resistance is 0.5 Ω. What is its EMF?

Solution:

$$\varepsilon = V + Ir = 8.5 + (3)(0.5) = 8.5 + 1.5 = 10.0 \text{ V}$$

Example 3: Charging Terminal Voltage

Problem: A 6 V lead-acid battery with internal resistance 0.02 Ω is being charged at 10 A. What is the terminal voltage?

Solution:

$$V = \varepsilon + Ir = 6 + (10)(0.02) = 6 + 0.2 = 6.2 \text{ V}$$

Example 4: Variable Load

Problem: A 9 V battery has internal resistance 0.3 Ω. Find the terminal voltage when connected to: (a) $R = 10$ Ω (b) $R = 1$ Ω (c) $R = 0.1$ Ω

Solution:

(a) $I = \frac{9}{10 + 0.3} = 0.874$ A $$V = IR = (0.874)(10) = 8.74 \text{ V}$$

(b) $I = \frac{9}{1 + 0.3} = 6.92$ A $$V = IR = (6.92)(1) = 6.92 \text{ V}$$

(c) $I = \frac{9}{0.1 + 0.3} = 22.5$ A $$V = IR = (22.5)(0.1) = 2.25 \text{ V}$$

Observation: As load resistance decreases, terminal voltage drops significantly.

Related Concepts

Summary Table

Condition Formula Terminal Voltage vs EMF
Open circuit ($I = 0$) $V = \varepsilon$ Equal
Discharging ($I > 0$) $V = \varepsilon - Ir$ Less than
Charging ($I < 0$) $V = \varepsilon + Ir$ Greater than

Key Equations

Equation Description
$V = \varepsilon - Ir$ Terminal voltage when delivering current
$V = \varepsilon + Ir$ Terminal voltage when charging
$V = \varepsilon$ Terminal voltage at open circuit
$V = IR$ Terminal voltage across external load
$\varepsilon = I(R + r)$ Complete circuit EMF equation